3.20.51 \(\int \frac {(3+5 x)^2}{(1-2 x)^{3/2} (2+3 x)^2} \, dx\)

Optimal. Leaf size=68 \[ -\frac {1091 \sqrt {1-2 x}}{294 (3 x+2)}+\frac {121}{14 \sqrt {1-2 x} (3 x+2)}+\frac {134 \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )}{147 \sqrt {21}} \]

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Rubi [A]  time = 0.02, antiderivative size = 68, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {89, 78, 63, 206} \begin {gather*} -\frac {1091 \sqrt {1-2 x}}{294 (3 x+2)}+\frac {121}{14 \sqrt {1-2 x} (3 x+2)}+\frac {134 \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )}{147 \sqrt {21}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(3 + 5*x)^2/((1 - 2*x)^(3/2)*(2 + 3*x)^2),x]

[Out]

121/(14*Sqrt[1 - 2*x]*(2 + 3*x)) - (1091*Sqrt[1 - 2*x])/(294*(2 + 3*x)) + (134*ArcTanh[Sqrt[3/7]*Sqrt[1 - 2*x]
])/(147*Sqrt[21])

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 78

Int[((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> -Simp[((b*e - a*f
)*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/(f*(p + 1)*(c*f - d*e)), x] - Dist[(a*d*f*(n + p + 2) - b*(d*e*(n + 1)
+ c*f*(p + 1)))/(f*(p + 1)*(c*f - d*e)), Int[(c + d*x)^n*(e + f*x)^(p + 1), x], x] /; FreeQ[{a, b, c, d, e, f,
n}, x] && LtQ[p, -1] && ( !LtQ[n, -1] || IntegerQ[p] ||  !(IntegerQ[n] ||  !(EqQ[e, 0] ||  !(EqQ[c, 0] || LtQ
[p, n]))))

Rule 89

Int[((a_.) + (b_.)*(x_))^2*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[((b*c - a*
d)^2*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/(d^2*(d*e - c*f)*(n + 1)), x] - Dist[1/(d^2*(d*e - c*f)*(n + 1)), In
t[(c + d*x)^(n + 1)*(e + f*x)^p*Simp[a^2*d^2*f*(n + p + 2) + b^2*c*(d*e*(n + 1) + c*f*(p + 1)) - 2*a*b*d*(d*e*
(n + 1) + c*f*(p + 1)) - b^2*d*(d*e - c*f)*(n + 1)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] && (LtQ
[n, -1] || (EqQ[n + p + 3, 0] && NeQ[n, -1] && (SumSimplerQ[n, 1] ||  !SumSimplerQ[p, 1])))

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rubi steps

\begin {align*} \int \frac {(3+5 x)^2}{(1-2 x)^{3/2} (2+3 x)^2} \, dx &=\frac {121}{14 \sqrt {1-2 x} (2+3 x)}-\frac {1}{14} \int \frac {-247+175 x}{\sqrt {1-2 x} (2+3 x)^2} \, dx\\ &=\frac {121}{14 \sqrt {1-2 x} (2+3 x)}-\frac {1091 \sqrt {1-2 x}}{294 (2+3 x)}-\frac {67}{147} \int \frac {1}{\sqrt {1-2 x} (2+3 x)} \, dx\\ &=\frac {121}{14 \sqrt {1-2 x} (2+3 x)}-\frac {1091 \sqrt {1-2 x}}{294 (2+3 x)}+\frac {67}{147} \operatorname {Subst}\left (\int \frac {1}{\frac {7}{2}-\frac {3 x^2}{2}} \, dx,x,\sqrt {1-2 x}\right )\\ &=\frac {121}{14 \sqrt {1-2 x} (2+3 x)}-\frac {1091 \sqrt {1-2 x}}{294 (2+3 x)}+\frac {134 \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )}{147 \sqrt {21}}\\ \end {align*}

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Mathematica [A]  time = 0.05, size = 62, normalized size = 0.91 \begin {gather*} \frac {21 (1091 x+725)+134 \sqrt {21-42 x} (3 x+2) \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )}{3087 \sqrt {1-2 x} (3 x+2)} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(3 + 5*x)^2/((1 - 2*x)^(3/2)*(2 + 3*x)^2),x]

[Out]

(21*(725 + 1091*x) + 134*Sqrt[21 - 42*x]*(2 + 3*x)*ArcTanh[Sqrt[3/7]*Sqrt[1 - 2*x]])/(3087*Sqrt[1 - 2*x]*(2 +
3*x))

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IntegrateAlgebraic [A]  time = 0.14, size = 61, normalized size = 0.90 \begin {gather*} \frac {1091 (1-2 x)-2541}{147 (3 (1-2 x)-7) \sqrt {1-2 x}}+\frac {134 \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )}{147 \sqrt {21}} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[(3 + 5*x)^2/((1 - 2*x)^(3/2)*(2 + 3*x)^2),x]

[Out]

(-2541 + 1091*(1 - 2*x))/(147*(-7 + 3*(1 - 2*x))*Sqrt[1 - 2*x]) + (134*ArcTanh[Sqrt[3/7]*Sqrt[1 - 2*x]])/(147*
Sqrt[21])

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fricas [A]  time = 1.05, size = 66, normalized size = 0.97 \begin {gather*} \frac {67 \, \sqrt {21} {\left (6 \, x^{2} + x - 2\right )} \log \left (\frac {3 \, x - \sqrt {21} \sqrt {-2 \, x + 1} - 5}{3 \, x + 2}\right ) - 21 \, {\left (1091 \, x + 725\right )} \sqrt {-2 \, x + 1}}{3087 \, {\left (6 \, x^{2} + x - 2\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3+5*x)^2/(1-2*x)^(3/2)/(2+3*x)^2,x, algorithm="fricas")

[Out]

1/3087*(67*sqrt(21)*(6*x^2 + x - 2)*log((3*x - sqrt(21)*sqrt(-2*x + 1) - 5)/(3*x + 2)) - 21*(1091*x + 725)*sqr
t(-2*x + 1))/(6*x^2 + x - 2)

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giac [A]  time = 1.24, size = 68, normalized size = 1.00 \begin {gather*} -\frac {67}{3087} \, \sqrt {21} \log \left (\frac {{\left | -2 \, \sqrt {21} + 6 \, \sqrt {-2 \, x + 1} \right |}}{2 \, {\left (\sqrt {21} + 3 \, \sqrt {-2 \, x + 1}\right )}}\right ) - \frac {2 \, {\left (1091 \, x + 725\right )}}{147 \, {\left (3 \, {\left (-2 \, x + 1\right )}^{\frac {3}{2}} - 7 \, \sqrt {-2 \, x + 1}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3+5*x)^2/(1-2*x)^(3/2)/(2+3*x)^2,x, algorithm="giac")

[Out]

-67/3087*sqrt(21)*log(1/2*abs(-2*sqrt(21) + 6*sqrt(-2*x + 1))/(sqrt(21) + 3*sqrt(-2*x + 1))) - 2/147*(1091*x +
725)/(3*(-2*x + 1)^(3/2) - 7*sqrt(-2*x + 1))

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maple [A]  time = 0.01, size = 45, normalized size = 0.66 \begin {gather*} \frac {134 \sqrt {21}\, \arctanh \left (\frac {\sqrt {21}\, \sqrt {-2 x +1}}{7}\right )}{3087}+\frac {121}{49 \sqrt {-2 x +1}}+\frac {2 \sqrt {-2 x +1}}{441 \left (-2 x -\frac {4}{3}\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((5*x+3)^2/(-2*x+1)^(3/2)/(3*x+2)^2,x)

[Out]

121/49/(-2*x+1)^(1/2)+2/441*(-2*x+1)^(1/2)/(-2*x-4/3)+134/3087*arctanh(1/7*21^(1/2)*(-2*x+1)^(1/2))*21^(1/2)

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maxima [A]  time = 1.25, size = 65, normalized size = 0.96 \begin {gather*} -\frac {67}{3087} \, \sqrt {21} \log \left (-\frac {\sqrt {21} - 3 \, \sqrt {-2 \, x + 1}}{\sqrt {21} + 3 \, \sqrt {-2 \, x + 1}}\right ) - \frac {2 \, {\left (1091 \, x + 725\right )}}{147 \, {\left (3 \, {\left (-2 \, x + 1\right )}^{\frac {3}{2}} - 7 \, \sqrt {-2 \, x + 1}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3+5*x)^2/(1-2*x)^(3/2)/(2+3*x)^2,x, algorithm="maxima")

[Out]

-67/3087*sqrt(21)*log(-(sqrt(21) - 3*sqrt(-2*x + 1))/(sqrt(21) + 3*sqrt(-2*x + 1))) - 2/147*(1091*x + 725)/(3*
(-2*x + 1)^(3/2) - 7*sqrt(-2*x + 1))

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mupad [B]  time = 1.24, size = 46, normalized size = 0.68 \begin {gather*} \frac {\frac {2182\,x}{441}+\frac {1450}{441}}{\frac {7\,\sqrt {1-2\,x}}{3}-{\left (1-2\,x\right )}^{3/2}}+\frac {134\,\sqrt {21}\,\mathrm {atanh}\left (\frac {\sqrt {21}\,\sqrt {1-2\,x}}{7}\right )}{3087} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((5*x + 3)^2/((1 - 2*x)^(3/2)*(3*x + 2)^2),x)

[Out]

((2182*x)/441 + 1450/441)/((7*(1 - 2*x)^(1/2))/3 - (1 - 2*x)^(3/2)) + (134*21^(1/2)*atanh((21^(1/2)*(1 - 2*x)^
(1/2))/7))/3087

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3+5*x)**2/(1-2*x)**(3/2)/(2+3*x)**2,x)

[Out]

Timed out

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